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 Delay time calculation for reverberationReferences : Posted by Andy MuchoNotes : This is from some notes I had scribbled down from a while back on automatically calculating diffuse delays. Given an intial delay line gain and time, calculate the times and feedback gain for numlines delay lines..Code : int numlines = 8; float t1 = 50.0; // d0 time float g1 = 0.75; // d0 gain float rev = -3*t1 / log10 (g1); for (int n = 0; n < numlines; ++n) { float dt = t1 / pow (2, (float (n) / numlines)); float g = pow (10, -((3*dt) / rev)); printf ("d%d t=%.3f g=%.3f\n", n, dt, g); } The above with t1=50.0 and g1=0.75 yields: d0 t=50.000 g=0.750 d1 t=45.850 g=0.768 d2 t=42.045 g=0.785 d3 t=38.555 g=0.801 d4 t=35.355 g=0.816 d5 t=32.421 g=0.830 d6 t=29.730 g=0.843 d7 t=27.263 g=0.855 To go more diffuse, chuck in dual feedback paths with a one cycle delay effectively creating a phase-shifter in the feedback path, then things get more exciting.. Though what the optimum phase shifts would be I couldn't tell you right now..

 CommentsAdded on : 11/09/08 by bob[ AT ]yahoob[ DOT ]comComment : Hello, when you say 'dual feedback paths with one cycle delay' do you mean dual as in stereo? And one cycle means one sample? My experiments have massive energy build up of energy unless the feedback was something like * 0.01, but there was still ringing in the sound. Can you hint a little more about what you mean? Thanks

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