### Fast log2

References : Posted by Laurent de Soras
Code :
inline float fast_log2 (float val)
{
assert (val > 0);

int * const  exp_ptr = reinterpret_cast <int *> (&val);
int          x = *exp_ptr;
const int    log_2 = ((x >> 23) & 255) - 128;
x &= ~(255 << 23);
x += 127 << 23;
*exp_ptr = x;

return (val + log_2);
}

from : tobybear[AT]web[DOT]de
comment : And here is some native Delphi/Pascal code that does the same thing: function fast_log2(val:single):single; var log2,x:longint; begin x:=longint((@val)^); log2:=((x shr 23) and 255)-128; x:=x and (not(255 shl 23)); x:=x+127 shl 23; result:=single((@x)^)+log2; end; Cheers Toby www.tobybear.de

from : henry[AT]cordylus[DOT]de
comment : instead of using this pointer casting expressions one can also use a enum like this: enum FloatInt { float f;

from : henry[AT]cordylus[DOT]de
comment : instead of using this pointer casting expressions one can also use a enum like this: enum FloatInt { float f; int l; } p; and then access the data with: p.f = x; p.l >>= 23; Greetings, Henry

from : henry[AT]cordylus[DOT]de
comment : Sorry : didnt mean enum, ment UNION !!!

from : Laurent de Soras
comment : More precision can be obtained by adding the following line just before the return() : val = map_lin_2_exp (val, 1.0f / 2); Below is the function (everything is constant, so most operations should be done at compile time) : inline float map_lin_2_exp (float val, float k) { const float a = (k - 1) / (k + 1); const float b = (4 - 2*k) / (k + 1); // 1 - 3*a const float c = 2*a; val = (a * val + b) * val + c; return (val); } You can do the mapping you want for the range [1;2] -> [1;2] to approximate the function log(x)/log(2).

from : Laurent de Soras
comment : Sorry I meant log(x)/log(2) + 1